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Return a reference to the underlying std::uint64_t,
or throw an exception.
std::uint64_t& as_uint64();
If is_uint64()
is true, returns a reference
to the underlying std::uint64_t,
otherwise throws an exception.
Constant.
Strong guarantee.
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Type |
Thrown On |
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This function is intended for direct access to the underlying object,
if it has the type std::uint64_t.
It does not convert the underlying object to type std::uint64_t
even if a lossless conversion is possible. If you are not sure which
kind your value has,
and you only care about getting a std::uint64_t
number, consider using to_number instead.